SOLUTION: A1. A balloon is rising vertically at a constant speed of 5 ft/sec. A boy is cycling along a straight road at a speed of 15 ft/sec. When he passes under the balloon, it is 45 ft ab
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-> SOLUTION: A1. A balloon is rising vertically at a constant speed of 5 ft/sec. A boy is cycling along a straight road at a speed of 15 ft/sec. When he passes under the balloon, it is 45 ft ab
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Question 1040093: A1. A balloon is rising vertically at a constant speed of 5 ft/sec. A boy is cycling along a straight road at a speed of 15 ft/sec. When he passes under the balloon, it is 45 ft above him. How fast is the distance between the boy and the balloon increasing 3 seconds later?
Thankyou! Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! When he is directly under the balloon, the distance
between them is changing at ft/sec because
his speed in the vertical direction is zero
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In 3 sec, ballon is at ft plus ft ft above the boy
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In 3 sec the boy travels ft
---------------------- , so this is a 3 - 4 - 5 triangle
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The component of the balloon's speed along the
line between them is: ft/sec ( away from the boy )
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The component of the boy's speed along the
line between them is: ft/sec
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The distance between them is increasing at ft/sec
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I didn't draw it out, but that would help.
Hope I got it )
