SOLUTION: A set U is partitioned into two subsets, G and H. The number of elements in H is four times that in G. If n(U)=60, find n(H).

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Question 986710: A set U is partitioned into two subsets, G and H. The number of elements in H is four times that in G. If n(U)=60, find n(H).
Found 2 solutions by Fombitz, MathLover1:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
H%2BG=60
4x%2Bx=60
5x=60
x=12
So H has 48 elements and G has 12 elements.

Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

The number of elements in H is four times that in G; so, H=4G
If n%28U%29=60+, then H%2BG=60
since H=4G, we have 4G%2BG=60=>5G=60=>G=60%2F5=>G=12
then H=4%2A12=>H=48