SOLUTION: help ive got no idea where to start There are 100 monsters. 38 of them are visible, the rest are invisible. Amongst the visible monsters, 16 glow red, 18 glow blue, 18 glow g

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Question 793898: help ive got no idea where to start

There are 100 monsters. 38 of them are visible, the rest are invisible. Amongst the visible
monsters, 16 glow red, 18 glow blue, 18 glow green, 7 glow red and blue, 5 glow blue and
green and 6 glow red and green. (Note that \16 glow red" should be interpreted as: 16
monsters glow red, but each of those monsters is free to glow other colours too. The other
numbers should also be interpreted in the same way).
One day the monsters that simultaneously glow with all three colours, decide to join forces
with the invisible monsters, to form a mighty army. How many monsters are in the army?

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The number of visible monster is said to be 38.
The rest of the 100 monsters is 100-38=62invisible monsters.

There are x monsters that simultaneously glow with all three colors, and they are counted in all the other numbers given.

There are also D monsters that glow with exactly 2 colors.

If you add
the 16 monsters that glow red, plus
the 18 monsters that glow blue, plus
the 18 monsters that glow green
you get 16%2B18%2B18=52.
That count of 52 glowing monsters exceeds the number of visible monsters.
If we were counting each visible monster just once we should add up to 38.
That means that some monsters are being counted more than once in that total of 52 because they glow with two or three colors at once.
The difference, 52-38=14 includes D (each dual color monster counted once), plus 2x (2 extra counts for each triple color monster), so
14=D%2B2x
Adding the numbers of monsters that glow with at least two colors at once we get
7%2B5%2B16=18. That includes D (each dual color monster counted once), plus 3x because each triple color monster is counted 3 times, once for each pair of colors.
So 18=D%2B3x
system%2814=D%2B2x%2C18=D%2B3x%29 --> x=18-14=4

That might army includes the 4 triple color monsters, plus the 62 invisible ones, for a total of 62%2B4=highlight%2866%29