SOLUTION: {{{ for which value satisfies the equation 10*a^2-b^2=1 when a is greater 40 and b is greater than 100}}}
Algebra ->
sets and operations
-> SOLUTION: {{{ for which value satisfies the equation 10*a^2-b^2=1 when a is greater 40 and b is greater than 100}}}
Log On
You can put this solution on YOUR website! For which value satisfies the equation when a is greater 40 and b is greater than 100?
:
Rearrange to
10a^2 = b^2 + 1
a^2 =
:
a =
let a > 40 > 40
Square both sides > 1600
b^2 + 1 > 1600 * 10
b^2 > 16000-1
b >
b = 127
Find a
10a^2 = b^2 + 1
10a^2 = 127^2 + 1
10a^2 = 16129 + 1
a^2 = 16130/10
a^2 = 1613
a =
a = 40.162