SOLUTION: Given the sets: vowels = {'a' ,'e', 'i', 'o', 'u'} and name = {'a', 'l', 'l, 'a', 'n'} Which is FALSE? - name ∪ vowels = {'a'} - 'a' ∈ (vowels ∩ name) - Th

Algebra ->  sets and operations -> SOLUTION: Given the sets: vowels = {'a' ,'e', 'i', 'o', 'u'} and name = {'a', 'l', 'l, 'a', 'n'} Which is FALSE? - name ∪ vowels = {'a'} - 'a' ∈ (vowels ∩ name) - Th      Log On


   



Question 606645: Given the sets:
vowels = {'a' ,'e', 'i', 'o', 'u'} and name = {'a', 'l', 'l, 'a', 'n'}
Which is FALSE?
- name ∪ vowels = {'a'}
- 'a' ∈ (vowels ∩ name)
- The cardinality of name = The cardinality of {'a', 'l', 'n' }
- The cardinality of vowels is equal to the cardinality of name.
I would think it was D because the cardinality of vowels would be 5 and the cardinality of name would be 3, due to having more than one of the same letter.

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Given the sets:
vowels = {'a' ,'e', 'i', 'o', 'u'} and name = {'a', 'l', 'l, 'a', 'n'}
Which is FALSE?
- name ∪ vowels = {'a'}
That's false because (name ∪ vowels) = {'a', 'e', 'i', 'l', 'n', 'o','u'}

- 'a' ∈ (vowels ∩ name)
That's true because (vowels ∩ name) = {'a'} and 'a' ∈ {'a'}

- The cardinality of name = The cardinality of {'a', 'l', 'n' }
That's true because 'a', 'l', and 'n' are the only elements in the
set name, and that cardinality is 3.

- The cardinality of vowels is equal to the cardinality of name.
That's false because the cadinality of vowels is 5 and the cardinality
of names is only 3.


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I would think it was D because the cardinality of vowels would be 5 and the cardinality of name would be 3, due to having more than one of the same letter
Yes, but the first one is also false.

Edwin