SOLUTION: Select the statement that is not true A{l,a,t,e,r} B={l,a,t,e} C= {t,a,l,e} D= {e,a,t} E= {t,e,a} I tried to solve the problem on my own and I came up with d={e,a,t,}E={t,e,a

Algebra ->  sets and operations -> SOLUTION: Select the statement that is not true A{l,a,t,e,r} B={l,a,t,e} C= {t,a,l,e} D= {e,a,t} E= {t,e,a} I tried to solve the problem on my own and I came up with d={e,a,t,}E={t,e,a      Log On


   



Question 434054: Select the statement that is not true
A{l,a,t,e,r} B={l,a,t,e} C= {t,a,l,e} D= {e,a,t} E= {t,e,a}
I tried to solve the problem on my own and I came up with d={e,a,t,}E={t,e,a} not is true? Is this correct?

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!

NO!

 {e,a,t} = {t,e,a} = {a,t,e} = {a,e,t} = {e,t,a} = (t,a,e}}

All those are equal because they all have the EXACT same elements.
The order in which they are listed does not matter. Also, it doesn't
matter if an element is listed more than once.  {e,a,t} = {e,e,t,a,a,t,t,e}

{l,a,t,e} = {t,a,l,e} is true

However

{l,a,t,e,r} does NOT equal {l,a,t,e} 

{l,a,t,e,r} does NOT equal {t,a,l,e}

because the first set contains the element r and the second one doesn't.

However 

{l,a,t,e,r} = {a,l,t,e,r} is true.

Edwin