SOLUTION: Let A and B be sets. If elements of set A are also found in set B, then A is a subset of B. The textbook writes it this way: A ⊆ B Sample: A = {x, x + 1, x + 2}

Algebra ->  sets and operations -> SOLUTION: Let A and B be sets. If elements of set A are also found in set B, then A is a subset of B. The textbook writes it this way: A ⊆ B Sample: A = {x, x + 1, x + 2}       Log On


   

Question 1208386: Let A and B be sets. If elements of set A are also found in set B, then A is a subset of B.

The textbook writes it this way: A ⊆ B

Sample:

A = {x, x + 1, x + 2}

B = {a, b, c, x, x + 1, x + 2}

I see that the elements in set A are also in set B.

Conclusion: A ⊆ B

You say?
Answer by math_tutor2020(3816) About Me  (Show Source):
You can put this solution on YOUR website!

You are correct. Anything inside set A is also in set B.
It might help to highlight the items you want to focus on.
A = {x, x + 1, x + 2}
B = {a, b, c, x, x + 1, x + 2}

This is what the Euler Diagram would look like

circle A is entirely inside circle B.
x,x+1,x+2 are in circle A. By extension they are also in circle B.
a,b,c are in circle B, but outside circle A.