SOLUTION: question 1 find the value(s) of x for which
((x^3-7x^2+6x)/(x^5+4x^4-3))=0
question 2 determine the limiting value of (3n^2+1)/(4(n^2-2)) as n=∞
Algebra ->
sets and operations
-> SOLUTION: question 1 find the value(s) of x for which
((x^3-7x^2+6x)/(x^5+4x^4-3))=0
question 2 determine the limiting value of (3n^2+1)/(4(n^2-2)) as n=∞
Log On
Question 1106383: question 1 find the value(s) of x for which
((x^3-7x^2+6x)/(x^5+4x^4-3))=0
question 2 determine the limiting value of (3n^2+1)/(4(n^2-2)) as n=∞ Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Look for values that make the numerator equal to zero.
Potential zeros: x=0, x=1, x=6.
Verify that the denominator does not equal zero for any of these potential zeros.
If it doesn't, then it's a real zero.
.
.
.
