SOLUTION: How many seven digit numbers are there when 0 and 7 cannot be the leading number?

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Question 1050878: How many seven digit numbers are there when 0 and 7 cannot be the leading number?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
there are 10 digits from 0 to 9
when 0 and 7 cannot be the leading number, then there is 8 choices for the first digit and they are: 1, 2,+3, 4, 5, 6, 8, and 9
there will be 10 choices for each of the remaining 6 digits, and we have:
8%2A10%5E6+=+8000000
or, you can do it this way:
Position: 1st.. 2nd ..3rd.. 4th.. 5th.. 6th ..7th
choices....8+.... 10......+10..... +10+......+10....+10..... 10
total number of choices: 8+%2A+10+%2A+10+%2A+10+%2A+10+%2A+10+%2A+10+=8%2A1000000=8000000