SOLUTION: I've been on this problem for almost 2 hours and I'm getting more and more frustrated. Solve each of the following systems by substitution 28. 4x - 12y = 5 -x + 3y = -1 Thi

Algebra ->  sets and operations -> SOLUTION: I've been on this problem for almost 2 hours and I'm getting more and more frustrated. Solve each of the following systems by substitution 28. 4x - 12y = 5 -x + 3y = -1 Thi      Log On


   



Question 103599: I've been on this problem for almost 2 hours and I'm getting more and more frustrated.
Solve each of the following systems by substitution
28.
4x - 12y = 5
-x + 3y = -1
This is one of the answers I got, but none of my answers are right when I try to check them
y = -x - (-1)/3
y = -x +1/3
4x - 12(-x +1/3) = 5
4x + 12x (-12)/3 = 5
16x - 12x / 3 = 5
4x/ 3= 5
4x = 5(3)
x = 15/4
x = 3.75
What am I missing??? Please advise...
Thank you Rev. B

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
A) 4x - 12y = 5
B) -x + 3y = -1
.
B) -x=-3y-1
x=3y+1
.
4(3y+1)-12y=5
12y+4-12y=5
0y=1
.
There is no answer to this system. Why? Because these 2 lines have the same slope. They are parallel.
A) y=x/3-(5/12)
B) y=x/3-(1/3)
the slope is 1/3 for both equations.
Ed
.
graph%28500%2C500%2C-5%2C5%2C-5%2C5%2C%28x%2F3%29-%285%2F12%29%2Cx%2F3-%281%2F3%29%29