SOLUTION: Find four consecutive odd integers such that the sum of two largest integers subtracted from twice the sum of the two smallest integers is 96

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Question 941016: Find four consecutive odd integers such that the sum of two largest integers subtracted from twice the sum of the two smallest integers is 96

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the 4 consecutive odd integers be:
+n+, +n%2B2+, +n+%2B+4+, and +n+%2B+6+
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given:
+n+%2B+4+%2B+n+%2B+6+-+2%2A%28+n+%2B+n+%2B+2+%29+=+96+
+2n+%2B+10+-+2%2A%28+2n+%2B+2+%29+=+96+
+2n+%2B+10+-+4n+-+4+=+96+
+-2n+%2B+6+=+96+
+-2n+=+90+
+n+=+-45+
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The number are:
-45, -43, -41, -39
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check the answer:
+n+%2B+4+%2B+n+%2B+6+-+2%2A%28+n+%2B+n+%2B+2+%29+=+96+
+-41+-+39+-+2%2A%28+-45+-43+%29+=+96+
+-80+-+2%2A%28+-88+%29+=+96+
+-80+%2B+176+=+96+
+96+=+96+
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Hope you can follow it