SOLUTION: Start from 110 feet away, a person on a scooter rides towards a checkpoint and then passes it. The rider is traveling at a constant rate of 30 feet per second. The distance between
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Question 909243: Start from 110 feet away, a person on a scooter rides towards a checkpoint and then passes it. The rider is traveling at a constant rate of 30 feet per second. The distance between the scooter and the checkpoint is given by the equation d = (110-30t). At what seconds is the bike 40 feet away from the checkpoint? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! d = (110-30t)
At what seconds is the bike 40 feet away from the checkpoint?
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40 = 110 - 30t
Solve for t
