Question 85360: I have a question that states: find the maximum revenue for the revenue function R(x)=490x-0.07x^2. How do I do this?
Answer by Nate(3500) (Show Source):
You can put this solution on YOUR website! R(x) = 490x - 0.07x^2
This is a vertical parabola whose vertex would determine the maximum revenue.
v(-b/2a,R(x))
v(-490/0.14,R(x))
v(3500,R(3500))
v(3500,857500)
Max Rev: 857,500
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