SOLUTION: solve. Approximate irrational roots to the nearest tenth. The volume V of a pyramid varies jointly as its altitude H and the area of its base. A pyramid with a nine-inch square

Algebra ->  Real-numbers -> SOLUTION: solve. Approximate irrational roots to the nearest tenth. The volume V of a pyramid varies jointly as its altitude H and the area of its base. A pyramid with a nine-inch square       Log On


   

Question 44161: solve. Approximate irrational roots to the nearest tenth.
The volume V of a pyramid varies jointly as its altitude H and the area of its base. A pyramid with a nine-inch square base (a square base 9 inches on each side) and an altitude of 10 inches has a volume equal to 270 in^3. Find the volume of a pyramid with an altitude of 6 inches and a square base 4 inches on each side. (units optional)
Answer by fractalier(6550) About Me  (Show Source):
You can put this solution on YOUR website!
The joint relationship can be expressed as
V = kbh (here b = s^2)
now plug in what we know to find k...
270 = k(81)(10) so that
k = 1/3
Now rewrite using the new k and the data to find the new volume...
V = (1/3)bh
V = (1/3)(16)(6)
V = 32 in^3