SOLUTION: 3(-K-4)+6=K+7 3*k=3k 3*4=12 3k-12+6=k+7 4k=1

Algebra ->  Real-numbers -> SOLUTION: 3(-K-4)+6=K+7 3*k=3k 3*4=12 3k-12+6=k+7 4k=1      Log On


   

Question 22414: 3(-K-4)+6=K+7 3*k=3k 3*4=12 3k-12+6=k+7 4k=1
Answer by ferd(1) About Me  (Show Source):