SOLUTION: ok, I need to find the intercept And the roots of this equation...
y=20x^2 - 282(x) + 1000
so that is again y= 20 multiplied by x squared minus 282 multiplied by x plus 1000
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-> SOLUTION: ok, I need to find the intercept And the roots of this equation...
y=20x^2 - 282(x) + 1000
so that is again y= 20 multiplied by x squared minus 282 multiplied by x plus 1000
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Question 172591: ok, I need to find the intercept And the roots of this equation...
y=20x^2 - 282(x) + 1000
so that is again y= 20 multiplied by x squared minus 282 multiplied by x plus 1000
I know they are imaginary roots but i cannot for the life of me figure this out!! PLEASE HELP Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! find the intercept And the roots of this equation...
y=20x^2 - 282(x) + 1000
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y-intercept: (0,1000)
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To find the x-intercepts use the quadratic formula:
20x^2 - 282x + 1000 = 0
10x^2 - 141x + 500 = 0
x = [141 +- sqrt(141^2 - 4*10*500)]/20
x = [141 +- sqrt(-119)]/20
x = [141 +- isqrt(119)]/20
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Cheers,
Stan H.
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