SOLUTION: Hi, can someone please confirm . I just asked a question on imaginary numbers . Simplify {{{ (5-3i)/(-3-2i) }}} . Put in complex number form {{{ a + bi }}} . The answer I g

Algebra ->  Real-numbers -> SOLUTION: Hi, can someone please confirm . I just asked a question on imaginary numbers . Simplify {{{ (5-3i)/(-3-2i) }}} . Put in complex number form {{{ a + bi }}} . The answer I g      Log On


   

Question 159169: Hi, can someone please confirm
.
I just asked a question on imaginary numbers
.
Simplify +%285-3i%29%2F%28-3-2i%29+
.
Put in complex number form +a+%2B+bi+
.
The answer I got, was +-9%2F13%2B%2819%2F13%29i+ (Isn't +i%5E2+ = (-1))
.
Can you please confirm my answer.
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Thanks ahead of time,Levi
Answer by gonzo(654) About Me  (Show Source):
You can put this solution on YOUR website!
i got the same answer as you although i kept the denominator as 1 number.
original equation is %285-3%2Ai%29%2F%28-3-2%2Ai%29
i multiplied top and bottom by %28-3%2B2i%29 to remove imaginary number from the denominator.
result was %28-9%2B19%2Ai%29%2F13
which is the same answer you got.
looks good from what i can tell.
i%5E2=%28-1%29 is correct.