SOLUTION: ok im stuck on what to do next heres the problem and what i have so far problem: 3/x^2+4x-5 minus 2x/x-1= here's what i have so far i found the LCD which is (x-1)(x+5)

Algebra ->  Real-numbers -> SOLUTION: ok im stuck on what to do next heres the problem and what i have so far problem: 3/x^2+4x-5 minus 2x/x-1= here's what i have so far i found the LCD which is (x-1)(x+5)       Log On


   

Question 121531This question is from textbook intro & intermediate algebra
: ok im stuck on what to do next heres the problem and what i have so far
problem: 3/x^2+4x-5 minus 2x/x-1=
here's what i have so far i found the LCD which is (x-1)(x+5)
3/(x+5)(x-1)minus 2x(x+5)/(x-1)(x+5)=
3-2x^2+5x/(x-1)(x+5)
and there is where i got stuck!
thanks in advance!


This question is from textbook intro & intermediate algebra

Answer by algebrapro18(249) About Me  (Show Source):
You can put this solution on YOUR website!
you started out great but messed up a little bit in your algebra, here is how it should be worked out.

%283%2F%28x%5E2%2B4x-5%29%29+-+%28%282x%29%2F%28x-1%29%29 ---> Factor the denominator
%283%2F%28%28x-1%29%28x%2B5%29%29%29+-+%28%282x%29%2F%28x-1%29%29 ---> Multiply to get common denominator
%283+-+%282x%28x%2B5%29%29%29+%2F+%28%28x-1%29%28x%2B5%29%29 ---> Simplify
%283+-+2x%5E2+-10x%29%2F%28%28x-1%29%28x%2B5%29%29 ---> rewrite in proper form
%28-2x%5E2-10x%2B3%29%2F%28%28x-1%29%28x%2B5%29%29

thats as simplified as it gets.