SOLUTION: find the range of f(x) = sqrt(floor(x)-3)

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Question 1203870: find the range of f(x) = sqrt(floor(x)-3)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

the range of f%28x%29+=+sqrt%28floor%28x%29-3%29:
the floor function is the function that takes as input a real number x, all negative numbers are excluded
so, the range is:
{ f element R : f%3E=0 } (all non-negative real numbers)