SOLUTION: The sum of three numbers is 137. The second number is 4 more that two times the first number. The third number is 5 less than three times the first number. Find the three numb

Algebra ->  Real-numbers -> SOLUTION: The sum of three numbers is 137. The second number is 4 more that two times the first number. The third number is 5 less than three times the first number. Find the three numb      Log On


   

Question 118585This question is from textbook Algebra 1
:
The sum of three numbers is 137. The second number is 4 more that two times the first number. The third number is 5 less than three times the first number. Find the three numbers.
Thank you for your help! This question is from textbook Algebra 1

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
LET X BE THE FIRST NUMBER
LET (4+2X) BE THE SECOND NUMBER
LET (3X-5) BE THE THIRD NUMBER
THUS WE HAVE:
X+(4+2X)+(3X-5)=137
6X-1=137
6X=137+1
6X=138
X=138/6
X=23 ANSWER FOR THE FIRST NUMBER.
4+2*23=4+46=50 FOR THE SECOND NUMBER.
3*23-5=69-5=64 FOR THE THIRD NUMBER.
PROOF
23+50+64=137
137=137