SOLUTION: The height of a cannonball shot upward from a height of 14 feet above the ground with an initial velocity of 60 feet/second is given by the equation
h equals negative 16 t squ
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h equals negative 16 t squ
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Question 1143296: The height of a cannonball shot upward from a height of 14 feet above the ground with an initial velocity of 60 feet/second is given by the equation
h equals negative 16 t squared plus 60 t plus 14
h=−16t2+60t+14.
After how many seconds will the cannonball be 30 feet above the ground? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The height of a cannonball shot upward from a height of 14 feet above the ground with an initial velocity of 60 feet/second is given by the equation
h equals negative 16 t squared plus 60 t plus 14
h=−16t2+60t+14.
After how many seconds will the cannonball be 30 feet above the ground?
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h(t) = −16t^2+60t+14
−16t^2+60t+14 = 30
Solve for t
