SOLUTION: Each of three boxes has 10 balls with numbers from 0 to 9. You take out one ball from each box randomly. What is the probability that you have taken out a. three “2”s? b. 3 numbe

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Question 1120139: Each of three boxes has 10 balls with numbers from 0 to 9. You take out one ball from each box randomly. What is the probability that you have taken out
a. three “2”s?
b. 3 numbers that are the same?

Answer by math_helper(2461)   (Show Source): You can put this solution on YOUR website!

a) (1/10)*(1/10)*(1/10) = = 0.001
b) (1/10)*(1/10) = = 0.01
Notice for part(b) that the first pick is x (where x=0,1,…9), so only the 2nd and 3rd picks need to match x. In contrast, part(a) stipulates that x=2 so we have a 1/10 probability of picking that particular x on pick #1.


An alternate way to view (b) vs (a): there are 10 possible picks where the 3 numbers match, and only one {2,2,2}, so the answer to (b) must be 10 times as great as (a).


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