SOLUTION: A rectangle’s length is about 19 inches greater than its width. If the perimeter is 50 inches, what is the area of the rectangle?
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Question 1049886: A rectangle’s length is about 19 inches greater than its width. If the perimeter is 50 inches, what is the area of the rectangle? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there,
Make width = x
Length = 19 + x
Perimeter = 2 x Width + 2 x Length
50 = 2(x) + 2(19 + x)
50 = 2x + 38 + 2x
4x = 12
x = 3.
Width = 3 inches
Length = 22 inches.
Area = Width x Length
Area = 3 x 22
Width = 66 inches^2
Hope this helps :-)
