SOLUTION: Can you solve (z-9)^(4/3)=3 ? where z is a real number. It may have more than one answer.

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Question 1041733: Can you solve (z-9)^(4/3)=3 ? where z is a real number. It may have more than one answer.
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!


Raise both sides to the reciprocal of 4%2F3 power,
which is the 3%2F4 power in order to cancel the
4%2F3 power:



To remove the parentheses on the left, multiply the
exponents:



Multiply matrix%281%2C3%2C4%2F3%2C%22%22%2A%22%22%2C3%2F4%29 and get just 1





Add 9 to both sides:



If you like you can write the fractional
exponent as a root with index the same as
the denominator and the radicand as the
base with the exponent the same as
the numerator:



Then you can write the 33 as 27:




Edwin