SOLUTION: the engine in Paul's weed whacker uses an oil gas mixture. The owners manual recommends using the oil and gasoline together, using the size of the oil container to guide how much o

Algebra ->  Real-numbers -> SOLUTION: the engine in Paul's weed whacker uses an oil gas mixture. The owners manual recommends using the oil and gasoline together, using the size of the oil container to guide how much o      Log On


   

Question 1020063: the engine in Paul's weed whacker uses an oil gas mixture. The owners manual recommends using the oil and gasoline together, using the size of the oil container to guide how much of each to use. It states to use 1/8 part oil with 4 parts gasoline. Paul buys a 32 ounce contained of oil. How large a container will he need to hold the mixture if the amount of oil he uses is 1/8 of the oil container.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+%281%2F8%29%2A32+=+4+ ounces of oil
[ ounces of oil ] / [ ounces of gas ] = +%28%281%2F8%29%29+%2F+4+
+%28%281%2F8%29%29+%2F+4+=+1%2F32+
--------------------
[ ounces of oil ] / [ ounces of gas ] = +1%2F32+
Let +g+ = ounces of gas needed
+4+%2F+g+=+1%2F32+
+4%2A32+=+g+
+g+=+128+
You have 128 ounces of gas and 4 ounces of oil, so
the container has to hold 132 ounces