Tutors Answer Your Questions about Quadratic Equations (FREE)
Question 1042680: Hi, I'm having a really difficult time understanding how to convert a Quadratic from Standard form to Vertex form. I've watched videos and have read multiple websites explaining it but either the videos are too fast, or the lesson is too confusing. I was wondering if there would be any way you could explain the steps in converting standard form to vertex form as simple as possible? Thank you so so much!!
Click here to see answer by Boreal(15235)   |
Question 1042680: Hi, I'm having a really difficult time understanding how to convert a Quadratic from Standard form to Vertex form. I've watched videos and have read multiple websites explaining it but either the videos are too fast, or the lesson is too confusing. I was wondering if there would be any way you could explain the steps in converting standard form to vertex form as simple as possible? Thank you so so much!!
Click here to see answer by stanbon(75887) |
Question 1042559: Calculators are sold to students for 1000 dollars each. Five hundred students are willing to buy them at that price. For every 20 dollar increase in price, there are 30 fewer students willing to buy the calculator.
a. What selling price will produce the maximum revenue and what will be the maximum revenue?
b. Show and illustrate the table of values, equation and graph for the revenue function.
c.State the domain, range, and x-intercepts of the graph.
Click here to see answer by stanbon(75887) |
Question 1042685: Can somebody walk me through a step on this quadratic word problem?
A small motorboat travels 13 mph in still water. It takes 2 hours longer to travel 60 miles going upstream than it does going downstream. Find the rate of the current.
I am at a point where I have:
60/13-x - 60/13+x =2
I know that I need to multiply both sides of the equation by the LCD and that it will turn into:
2x^2+20x-338=0
But I just cant seem to figure out HOW to actually do that. I think the denominators of 13-x/13+x are really throwing me.
Or if somebody has an easier way to get to the quadratic equation in this word problem I am all ears.
Thanks so much in advance!
Click here to see answer by ikleyn(52754)  |
Question 1042685: Can somebody walk me through a step on this quadratic word problem?
A small motorboat travels 13 mph in still water. It takes 2 hours longer to travel 60 miles going upstream than it does going downstream. Find the rate of the current.
I am at a point where I have:
60/13-x - 60/13+x =2
I know that I need to multiply both sides of the equation by the LCD and that it will turn into:
2x^2+20x-338=0
But I just cant seem to figure out HOW to actually do that. I think the denominators of 13-x/13+x are really throwing me.
Or if somebody has an easier way to get to the quadratic equation in this word problem I am all ears.
Thanks so much in advance!
Click here to see answer by Boreal(15235) |
Question 1042685: Can somebody walk me through a step on this quadratic word problem?
A small motorboat travels 13 mph in still water. It takes 2 hours longer to travel 60 miles going upstream than it does going downstream. Find the rate of the current.
I am at a point where I have:
60/13-x - 60/13+x =2
I know that I need to multiply both sides of the equation by the LCD and that it will turn into:
2x^2+20x-338=0
But I just cant seem to figure out HOW to actually do that. I think the denominators of 13-x/13+x are really throwing me.
Or if somebody has an easier way to get to the quadratic equation in this word problem I am all ears.
Thanks so much in advance!
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 1042685: Can somebody walk me through a step on this quadratic word problem?
A small motorboat travels 13 mph in still water. It takes 2 hours longer to travel 60 miles going upstream than it does going downstream. Find the rate of the current.
I am at a point where I have:
60/13-x - 60/13+x =2
I know that I need to multiply both sides of the equation by the LCD and that it will turn into:
2x^2+20x-338=0
But I just cant seem to figure out HOW to actually do that. I think the denominators of 13-x/13+x are really throwing me.
Or if somebody has an easier way to get to the quadratic equation in this word problem I am all ears.
Thanks so much in advance!
Click here to see answer by stanbon(75887) |
Question 1042813: Could you help me solve ??
The cost of a can of Coca-Cola on January 1, 1960 , was 10 cents. The function  gives the cost of a can of Coca-Cola, C(t), t years after that.
a.) How much did a can of Coca Cola cost in 1975 (round to nearest penny)?
b.) In what year will a can of Coca-Cola cost $1.00 (round to nearest whole year).
c.) How much does a can of Coca-Cola cost in 2045 ?
Thank you so much !!
Click here to see answer by stanbon(75887) |
Question 1042813: Could you help me solve ??
The cost of a can of Coca-Cola on January 1, 1960 , was 10 cents. The function gives the cost of a can of Coca-Cola, C(t), t years after that.
a.) How much did a can of Coca Cola cost in 1975 (round to nearest penny)?
b.) In what year will a can of Coca-Cola cost $1.00 (round to nearest whole year).
c.) How much does a can of Coca-Cola cost in 2045 ?
Thank you so much !!
Click here to see answer by Edwin McCravy(20054)  |
Question 1043163: A triangular sail for a yacht needs to have a surface area of 84m squared. The base length X+8 relative to the vertice height of the sale which is 2x+6 where the value of X in metres is not known. Use your knowledge of quadratic functions to find the value of X and determine the length of the base and the vertical height of the sail.
Click here to see answer by ankor@dixie-net.com(22740) |
Question 1043259: a bungee jumper leaps off a cliff 122 meters from the ground. her cord, when fully stretched, is 72 meters long, and it takes 6 seconds after the jump for it to extend fully. the distance between the jumper and the ground as a function of time can be modeled as a quadratic function. what is the equation represents her distance from the ground as a function of time?
Click here to see answer by stanbon(75887) |
Question 1043586: I have worked out the quadratic equation for
x= -3q^2+150q, where q is quantity. The question asks what is the quantity is if x = 150? So I'm basically being asked what is p? I got:
q= 5(5 - radical 7) / 3 , q= 5(5 + radical 7) / 3
q=3.92375, q=12.74292.
But I don't know if that's the final answer to the question, or do I have to pick one of those two decimals?
Click here to see answer by ikleyn(52754) |
Question 1043584: I have worked out the quadratic equation for
x= -3q^2+150q, where q is quantity. The question asks what is the quantity is if x = 150? So I'm basically being asked what is q? I got:
q= 5(5 - radical 7) / 3 , q= 5(5 + radical 7) / 3
q=3.92375, q=12.74292.
But I don't know if that's the final answer to the question, or do I have to pick one of those two decimals?
Click here to see answer by ikleyn(52754) |
Question 1043584: I have worked out the quadratic equation for
x= -3q^2+150q, where q is quantity. The question asks what is the quantity is if x = 150? So I'm basically being asked what is q? I got:
q= 5(5 - radical 7) / 3 , q= 5(5 + radical 7) / 3
q=3.92375, q=12.74292.
But I don't know if that's the final answer to the question, or do I have to pick one of those two decimals?
Click here to see answer by Edwin McCravy(20054) |
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