SOLUTION: The product of two consecutive odd integers is 58 less than the square of the next consecutive integer. Find the three integers.

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Question 987129: The product of two consecutive odd integers is 58 less than the square of the next consecutive integer. Find the three integers.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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x and x+2 are consecutive odd integers. x+4=next consecutive odd integer.
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%28x%29%28x%2B2%29=%28x%2B4%29%5E2-58
x%5E2%2B2x=x%5E2%2B8x%2B16-58%7D%7D%0D%0A%7B%7B%7B0=6x-42
0=x-7
7=x
ANSWER 1: the first integer is 7.
second integer=x+2=7+2=9
ANSWER 2: The second integer is 9.
third integer=x+4=7+4=11
ANSWER 3: The third integer is 11.
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CHECK:
%287%29%289%29=%2811%29%5E2-58
63=121-58
63=63