SOLUTION: find two positive real numbers that differ by 1 and have a product of 1

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Question 98170: find two positive real numbers that differ by 1 and have a product of 1
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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ind two positive real numbers that differ by 1 and have a product of 1
:
The two numbers x, (x-1)
:
The product = 1
x(x-1) = 1
x^2 - x = 1
x^2 - x - 1 = 0, a quadratic equation, solve using formula
:
x+=+%28-%28-1%29+%2B-+sqrt%28+-1%5E2+-+4+%2A+1+%2A-1+%29%29%2F%282%2A1%29+
:
x+=+%28%2B1+%2B-+sqrt%28%2B1+%2B+4+%29%29%2F%282%29+
:
Two solutions
x+=+%28%2B1+%2B+sqrt%285%29%29%2F%282%29+
and
x+=+%28%2B1+-+sqrt%285%29%29%2F%282%29+
:
The two numbers, approx, +1.618 and +.618
or
The two numbers, approx, -.618 and -1.618