SOLUTION: Find the length and width of a similar rectangular screen if the length is 10 meters more than 6 times its width, and the viewable area is 7,700 square meters. please help!

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Find the length and width of a similar rectangular screen if the length is 10 meters more than 6 times its width, and the viewable area is 7,700 square meters. please help!      Log On


   



Question 981119: Find the length and width of a similar rectangular screen if the length is 10 meters more than 6 times its width, and the viewable area is 7,700 square meters.
please help!

Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Not the finished solution...

w, width
L, length
system%28L=6%2B10w%2CwL=7700%29

You will form a quadratic equation in the process.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Find the length and width of a similar rectangular screen if the length is 10 meters more than 6 times its width, and the viewable area is 7,700 square meters.
please help!
Let width be W
Then length is: 6W + 10
Area (viewable) is 7,700 m, so we get: W(6W + 10) = 7700
6W%5E2+%2B+10W+=+7700
6W%5E2+%2B+10W+-+7700+=+0
2%283W%5E2+%2B+5W+-+3850%29+=+2%280%29 ------ Factoring out GCF, 2
3W%5E2+%2B+5W+-+3850+=+0
(W - 35)(3W + 110) = 0
W, or width = highlight_green%2835%29 m OR W+=+-+110%2F3 (ignore)
Length: 6(35) + 10, or 210 + 10, or highlight_green%28220%29 m