SOLUTION: Write an equation (a) in standard form and (b) in slope-intercept form for the line described. through (5,9), parallel to y=-4

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Write an equation (a) in standard form and (b) in slope-intercept form for the line described. through (5,9), parallel to y=-4      Log On


   

Question 978002: Write an equation (a) in standard form and (b) in slope-intercept form for the line described.
through (5,9), parallel to y=-4
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Since any two parallel lines have the same slope we know the slope of the unknown line is 0 (its from the slope of y=0%2Ax-4 which is also 0). Also since the unknown line goes through (5,9), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope and (x%5B1%5D,y%5B1%5D) is the given point



y-9=0%2A%28x-5%29 Plug in m=0, x%5B1%5D=5, and y%5B1%5D=9



y-9=0%2Ax-%280%29%285%29 Distribute 0



y-9=0%2Ax-0 Multiply



y=0%2Ax-0%2B9Add 9 to both sides to isolate y

y=0%2Ax%2B9 Combine like terms

So the equation of the line that is parallel to y=0%2Ax-4 and goes through (5,9) is y=0%2Ax%2B9


So here are the graphs of the equations y=0%2Ax-4 and y=0%2Ax%2B9



graph of the given equation y=0%2Ax-4 (red) and graph of the line y=0%2Ax%2B9(green) that is parallel to the given graph and goes through (5,9)



so, line y=9 is parallel to y=-4 and passes through (5,9)