SOLUTION: Please decide whether or not the equation has a circle as its graph. If it does, give the center and radius. If it does not, describe the graph. 4x^2-36x+4y^2+28y-14=0 Than

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Please decide whether or not the equation has a circle as its graph. If it does, give the center and radius. If it does not, describe the graph. 4x^2-36x+4y^2+28y-14=0 Than      Log On


   

Question 975981: Please decide whether or not the equation has a circle as its graph. If it does, give the center and radius. If it does not, describe the graph.
4x^2-36x+4y^2+28y-14=0
Thanks so much!
Found 2 solutions by Fombitz, aarontivey:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
4x%5E2-36x%2B4y%5E2%2B28y-14=0
4%28x%5E2-9x%29%2B4%28y%5E2%2B7y%29=14

4%28x-9%2F2%29%2B4%28x%2B7%2F2%29=14%2B324%2B196
4%28x-9%2F2%29%5E2%2B4%28x%2B7%2F2%29%5E2=534
%28x-9%2F2%29%5E2%2B%28y%2B7%2F2%29%5E2=267%2F2
Center : (9%2F2,-7%2F2)
Radius : sqrt%28267%2F2%29

Answer by aarontivey(2) About Me  (Show Source):
You can put this solution on YOUR website!
a circle has the equation x^2+y^2=R^2 where R is the radius of the circle
to get the equation in the form of this you would have to complete the square of x and y.
you would get (x-9/2)^2 + (y+7/2)^2 = 36
so the radius is root 36 witch is 6
the center is (9/2 ,-7/2)
hope this helps