SOLUTION: The problem is -4x^2+8x=0. So far I've done -4x^2+8x+7=0, 4x^2-8x-7=0 then I squared half of the coefficient of x and added to both sides and got 4x^2-8x+16=9 but I can't figure o

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: The problem is -4x^2+8x=0. So far I've done -4x^2+8x+7=0, 4x^2-8x-7=0 then I squared half of the coefficient of x and added to both sides and got 4x^2-8x+16=9 but I can't figure o      Log On


   

Question 97426This question is from textbook College Algebra
: The problem is -4x^2+8x=0. So far I've done -4x^2+8x+7=0, 4x^2-8x-7=0 then I squared half of the coefficient of x and added to both sides and got 4x^2-8x+16=9 but I can't figure out how to get a perfect square. Did I do something wrong in the first steps? This question is from textbook College Algebra

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
-4x^2+8x=0
Factor:
= -4x(x-2)=0
-4x=0 or x-2=0
x = 0 or x=2
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Cheers,
Stan H.