SOLUTION: In the equation x^2+10x+24=(x+a)(x+b), b is an interger. Find algebraically all possible values of b.

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Question 966335: In the equation x^2+10x+24=(x+a)(x+b), b is an interger. Find algebraically all possible values of b.
Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Factorize the left side member.

%28x%5E2%2B10x%2B24%29
%28x%2Bsomething%29%28x%2BsomethingElse%29

What are they? You have certain choices.
24=2%2A12=1%2A24=3%2A8=4%2A6;
What about the "10" for the "10x"?