Question 943701: A man built a walk of uniform width around a rectangular pool. If the area of the walk is 189 square feet and the dimensions of the pool are 6 feet by 6 feet, how wide is the walk?
Found 3 solutions by josgarithmetic, lwsshak3, MathTherapy:
Answer by josgarithmetic(39615)   (Show Source):
You can put this solution on YOUR website! u, the uniform width
w, the width of the pool
L, the length of the pool
b, the area of the walkway, think "border"
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w=6
L=6
b=189
find u, or solve for u.
Pool area,  ;
Pool Plus walkway/border area,  ;
Walkway area,  ;
The description gives w=L, so the last equation can be adjusted according to that simple substitution, the pool being square-shaped:
and then starting to simplify
 and you should know what to do from here... remember, the UNKNOWN variable is u.
Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! A man built a walk of uniform width around a rectangular pool. If the area of the walk is 189 square feet and the dimensions of the pool are 6 feet by 6 feet, how wide is the walk?
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let x=width of the walk
4x^2+4*6x=189
4x^2+24x-189=0
(2x-9)(2x+21)=0
2x-9=0
x=9/2=4.5
how wide is the walk? 4.5 ft
Answer by MathTherapy(10549)  (Show Source):
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