SOLUTION: Solve the quadratice equation by completing the square: x^2 - 6x - 3 = 0 x^2 - 6x = 3 x - 6x + 9 = 3 (x-3)^2 = 3 x - 3 = +/- radical 3 x = 3 +/- radical 3 Is this correct?

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Solve the quadratice equation by completing the square: x^2 - 6x - 3 = 0 x^2 - 6x = 3 x - 6x + 9 = 3 (x-3)^2 = 3 x - 3 = +/- radical 3 x = 3 +/- radical 3 Is this correct?      Log On


   

Question 89397This question is from textbook Beginning Algebra
: Solve the quadratice equation by completing the square:
x^2 - 6x - 3 = 0
x^2 - 6x = 3
x - 6x + 9 = 3
(x-3)^2 = 3
x - 3 = +/- radical 3
x = 3 +/- radical 3
Is this correct? This question is from textbook Beginning Algebra

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
There is an error on the step where you add 9 to the left side

x+-+6x+%2B+9+=+3

You need to add 9 to both sides to balance the equation

x+-+6x+%2B+9+=+3+%2B+highlight%289%29

x+-+6x+%2B+9+=+12 Add

%28x-3%29%5E2=+12 Factor the left side

x-3=0%2B-+sqrt%2812%29 Take the square root of both sides

x=3%2B-+sqrt%2812%29 Add 3 to both sides

x=3%2B-+2%2Asqrt%283%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)