SOLUTION: Solve the equation for x: x^2 + 4x + 4 = 7 (x + 2)(x + 2) = 7 (x + 2)^2 = 7 x + 2 = +/- radical 7 x = -2 +/- radical 7 Is this correct?
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-> SOLUTION: Solve the equation for x: x^2 + 4x + 4 = 7 (x + 2)(x + 2) = 7 (x + 2)^2 = 7 x + 2 = +/- radical 7 x = -2 +/- radical 7 Is this correct?
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Question 89386
This question is from textbook
Beginning Algebra
:
Solve the equation for x:
x^2 + 4x + 4 = 7
(x + 2)(x + 2) = 7
(x + 2)^2 = 7
x + 2 = +/- radical 7
x = -2 +/- radical 7
Is this correct?
This question is from textbook
Beginning Algebra
Answer by
jim_thompson5910(35256)
(
Show Source
):
You can
put this solution on YOUR website!
Yes it's correct. You can use other methods such as the quadratic formula to verify your answer.
So let's use the quadratic formula to solve for x:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve
( notice
,
, and
)
Plug in a=1, b=4, and c=-3
Square 4 to get 16
Multiply
to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this
solver
)
Multiply 2 and 1 to get 2
So now the expression breaks down into two parts
or
Now break up the fraction
or
Simplify
or
Notice we get the same answer. So our answer is verified.