SOLUTION: suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50. set up an equation for the perimeter involving L, the lengt

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50. set up an equation for the perimeter involving L, the lengt      Log On


   

Question 89143: suppose that the width of a rectangle is 5 inches shorter than the length and that the perimeter of the rectangle is 50. set up an equation for the perimeter involving L, the length of the rectangle. then solve algebraically.
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
W=L-5
2(L-5)+2L=50
2L-10+2L=50
4L=50+10
4L=60
L=60/4
L=15 ANSWER FOR THE LENGTH.
W=15-5
W-10 ANSWER FOR THE WIDTH.
PROOF
2*15+2*10=50
30+20=50
50=50