SOLUTION: hello, 1.What is the (x,y) coordinate of the maximum or minimum value of the following quadratic equation: -0.1x2 + 0.1x + 3 = y. 2.The derivative of y = ax2 + bx + c is

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: hello, 1.What is the (x,y) coordinate of the maximum or minimum value of the following quadratic equation: -0.1x2 + 0.1x + 3 = y. 2.The derivative of y = ax2 + bx + c is       Log On


   

Question 879481: hello,
1.What is the (x,y) coordinate of the maximum or minimum
value of the following quadratic equation: -0.1x2 + 0.1x + 3 = y.
2.The derivative of y = ax2 + bx + c is
a. y' = 2ax2 + 2bx + c
b. y' = 2ax + b

ax
c. y' = —— + bx
2

d. none of the above
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
y = -0.1x^2 + 0.1x + 3 Parabola opening downward -.1 < 0
y = -.1(x - 1/2)^2 + .025 + 3
Max(.5, 3.025)
y' = 2ax + b
y' = -.2x + .1
when y' = 0, x = 1/2