SOLUTION: Show that for all real values of a greater than 4,{{{x^2-2x a=3}}} will have nonreal roots.

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Question 879082: Show that for all real values of a greater than 4,x%5E2-2x+a=3 will have nonreal roots.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2-2ax-3=0
Use the discriminant, to have non-real roots, D%3C0
D=b%5E2-4ac
%28-2a%29%5E2-4%281%29%28-3%29%3C0
4a%5E2%2B12%3C0
a%5E2%2B3%3C0
There is no solution.
There are no real values of a that make this equation true.
Check your equation and repost if you need to.