SOLUTION: A ball is thrown upward from ground level with an initial velocity of 108 ft per sec. Its height H in feet after T seconds is given by the equation h = 16t^2 + 108t.At what time

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: A ball is thrown upward from ground level with an initial velocity of 108 ft per sec. Its height H in feet after T seconds is given by the equation h = 16t^2 + 108t.At what time       Log On


   

Question 861396: A ball is thrown upward from ground level with an initial velocity of 108 ft per sec. Its height H in feet after T seconds is given by the equation
h = 16t^2 + 108t.At what time will the ball hit the ground ?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The ball hits the ground when +h+=+0+
for the 2nd time. The 1st time was when
the ball was thrown upward
--------------------------
+h+=+-16t%5E2+%2B+108t+
+0+=+-16t%5E2+%2B+108t+
+0+=+-4t%5E2+%2B+27t+
+t%2A%28+27+-+4t+%29+=+0+
+4t+=+27+
+t+=+6.75+
The ball hits the ground in 6.75 sec
Here's the plot:
+graph%28+400%2C+400%2C+-2%2C+10%2C+-10%2C+200%2C+-16x%5E2+%2B+108x+%29+