SOLUTION: State the value of the discriminant for each equation. Then determine the number of real roots of the equation. 9a^2=6a-1

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Question 822696: State the value of the discriminant for each equation. Then determine the number of real roots of the equation. 9a^2=6a-1
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

state the value of the discriminant for each equation. 

Then determine the number of real roots of the equation. 

9a^2=6a-1

9a^2 - 6a + 1 = 0

+sqrt%28+b%5E2-4%2Aa%2Ac+%29+=+sqrt%2836+-+36%29+=+sqrt%280%29 

a+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+

a+=+%286%2F18%29+=+1%2F3 

There are ONE real root for this equation. V(1/3, 0)