SOLUTION: Problem: The length of a rectangle is 2 inches more than twice its width. If the perimeter of the rectangle is 34 inches, find the dimensions of the rectangle. Answer: W

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: Problem: The length of a rectangle is 2 inches more than twice its width. If the perimeter of the rectangle is 34 inches, find the dimensions of the rectangle. Answer: W      Log On


   

Question 81380: Problem:
The length of a rectangle is 2 inches more than twice its width. If the perimeter of the rectangle is 34 inches, find the dimensions of the rectangle.
Answer:

Width: ___________ inches

Length: ___________inches

Answer by askmemath(368) About Me  (Show Source):
You can put this solution on YOUR website!
Let the Width of the Rectange = W
Then length = 2W+2 since length of a rectangle is 2 inches more than twice its width
Perimeter of a rectangle = 2(Length +Width)
But this is given to be 34
So 2(Length +Width) = 34
or
2(2W+2 +W) = 34
Dividing on both sides with 2
3W+2 = 17
Subtracting 2 on both sides
3W = 15
Dividing on both sides with 3
W = 5
Which means Length = 12