Question 80827: can someone please check this for me?
(x-3)^2=9
=x=-3+-9
x=3+-sqrt9 Found 2 solutions by Earlsdon, stanbon:Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! Solve for x: Take the square root of both sides. (+ or -) or Add 3 to both sides of each equation. or or
You can put this solution on YOUR website! (x-3)^2=9
Write it as follows:
[(x-3)^2-9]=0
This is the difference of squares:
Factor as follows:
[x-3-3][x-3+3]=0
[x-6][x]=0
x=0 or x=6
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Another way to do it:
Expand it to get:
x^2-6x+9-9=0
x^2-6x=0
x(x-6)=0
x=0 or x=6
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Cheers,
Stan H.
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