SOLUTION: Please help with solving this problem--I'm lost.
When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t, where v is the initial upwards ve
Question 79393: Please help with solving this problem--I'm lost.
When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t, where v is the initial upwards velocity in feet per second. If v=36 feet per second, find all values of t for which h=19 feet. Do not round any intermediate steps. Round your answers to 2 decimal places.
Thanks so much!! Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! When a ball is thrown, its height in feet h after t seconds is given by the equation h=vt-16t, where v is the initial upwards velocity in feet per second. If v=36 feet per second, find all values of t for which h=19 feet. Do not round any intermediate steps. Round your answers to 2 decimal places.
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I think the equations would be: -16t^2 + 36t = 19
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-16t^2 + 36t - 19 = 0
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Find the value of t using the quadratic formula: a=-16; b=36; c=-19
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Two solutions:
t = +.85 sec (At 19' on the way up)
and
t = 1.40 sec (At 19' on the way down)
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Would look like this:
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Note that it shows about 19 ft at about .85 sec and 1.4 sec
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