SOLUTION: can you please check this for me? i am solving equation for x 2(x-5)^2=3 (x-5)^2=3/2 x-5=sqrt{{{3/2}}}=sqrt{{{6}}}/3 x=5sqrt{{{6}}}/3 x=15/3sqrt{{{6}}}/3 x=15sqrt{{{6}}}/3

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: can you please check this for me? i am solving equation for x 2(x-5)^2=3 (x-5)^2=3/2 x-5=sqrt{{{3/2}}}=sqrt{{{6}}}/3 x=5sqrt{{{6}}}/3 x=15/3sqrt{{{6}}}/3 x=15sqrt{{{6}}}/3      Log On


   



Question 79241: can you please check this for me? i am solving equation for x
2(x-5)^2=3
(x-5)^2=3/2
x-5=sqrt3%2F2=sqrt6/3
x=5sqrt6/3
x=15/3sqrt6/3
x=15sqrt6/3

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!


[First of all, the triple braces (three of these { before
and three of these } after) can be placed around the entire 
equations, including the sqrt's] : 

can you please check this for me? i am solving 
equation for x

2%28x-5%29%5E2=3
%28x-5%29%5E2=3%2F2

The next step should have ± before
the square root, because there are
TWO square roots of positive numbers,
not just one. You also should have a
2 on the bottom of the last fraction,
not a 3

+x-5 = ±sqrt%283%2F2%29 = ±sqrt%286%29%2F2

You also went wrong in the next step:
You got:  x=5%2Asqrt%286%29%2F3%29

That's wrong, other than just the wrong
denominator 3 instead of 2. You ADD 5 to 
both sides. You don't MULTIPLY.
That step should be:

x+=+5+%2B-+sqrt%286%29%2F2 

Edwin