Question 77444: Can someone please help me with this? Thanks
Graph the following equations and find:
The y-intercept.
The x-intercepts, if any.
The vertex.
The line of symmetry.
Solve for the y-intercept, x-intercepts (if any), the coordinates of the vertex, and the line of symmetry using the methods shown in the lesson.
y = x2 + 7x + 12
y = x2 - 8x + 6
y = - x2 + 6x - 5
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Graph the following equations and find:
The y-intercept.
The x-intercepts, if any.
The vertex.
The line of symmetry.
Solve for the y-intercept, x-intercepts (if any), the coordinates of the vertex, and the line of symmetry using the methods shown in the lesson.
y = x^2 + 7x + 12
-------------------
y-intercept: let x=0, then y=12
x-interdept: let y=0
(x+4)(x+3)=0
x=-4 or x=-3
--------------
Vertex:
y-12+? = x^2+7x+?
y-12+(7/2)^2 = x^2+7x+(7/2)^2
y-(1/4) = (x+(7/2))
Vertex at (-7/2,1/4)
--------
Line of symmetry:
x=-7/2
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Cheers,
Stan H.
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