SOLUTION: 4y^2+12y+5=0 How did they factor and get (2y+1)(2y+5)=0? How did they get 1 and 5 in factoring from the equation at the top? help please

Algebra ->  Quadratic Equations and Parabolas  -> Quadratic Equation Customizable Word Problems -> SOLUTION: 4y^2+12y+5=0 How did they factor and get (2y+1)(2y+5)=0? How did they get 1 and 5 in factoring from the equation at the top? help please      Log On


   

Question 757853: 4y^2+12y+5=0

How did they factor and get
(2y+1)(2y+5)=0? How did they get 1 and 5 in factoring from the equation at the top? help please
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
4y^2+12y+5=0
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You would have to use the Quadratic Formula:
y = [-12 +-sqrt(144-4*4*5)]/(2*4)
etc.
Cheers,
Stan H.