Question 703935: Find the equation of the parabola with vertex (-2,0) and y intercept 4.
Can you please help me? Thanks so much in advance
Found 2 solutions by josmiceli, Edwin McCravy:
Answer by josmiceli(19441)   (Show Source):
You can put this solution on YOUR website! First write down the general form
of a parabola, which is:
When in this form, the x-coordinate of the vertex
is at 
You are given that the vertex is at ( -2,0 ), so I can say
---------------
So far, I have:
The y-intercept occurs where  , so
You are given that the y-intercept is  , so
----------------
So far, I have:
Now I go back to the vertex at ( -2,0 )
--------------
Now I have all I need to write the equation
 answer
--------------
check:
Does it go through ( 0,4) ? ( the y-intercept )
OK
Here's the plot:
Answer by Edwin McCravy(20054)  (Show Source):
You can put this solution on YOUR website! Find the equation of the parabola with vertex (-2,0) and y intercept 4
y = a(x-h)² + k
Substitute (h,k) = (-2,0) and (x,y) = (0,4)
4 = a(0-(-2))² + 0
4 = a(2)²
4 = 4a
1 = a
Substitute for just a, h and k, not x or y
y = a(x-h)² + k
y = 1(x-(-2))² + 0
y = (x+2)²
Or you can multiply that out
y = x²+4x+4
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