SOLUTION: hello I would like to ask for help setting up a word problem. I know how to solve it once it is set as an equation but I sometimes have trouble getting them in the right format to
Question 703806: hello I would like to ask for help setting up a word problem. I know how to solve it once it is set as an equation but I sometimes have trouble getting them in the right format to get the correct answer. Here is the problem:
A computer keyboard is 11 in. longer than it is wide. If the length and width are increased by 2 in. the area is increased by 54 in. Find the length and width of the keyboard.
Thank you very much I really appreciate the help. I like to figure these out by myself but can't this one Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A computer keyboard is 11 in. longer than it is wide. If the length and width are increased by 2 in. the area is increased by 54 in. Find the length and width of the keyboard.
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Initial dimensions:
width = x
length = x+11
Area = x(x+11) = x^2+11x
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Modified dimensions:
width = x+2
length = x+13
Area = (x+2)(x+13) = x^2 + 15x + 26
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Equation:
new area - old area = 54 sq in
x^2 + 15x + 26 - (x^2+11x) = 54
4x + 26 = 54
4x = 28
x = 7 inches (original width)
x+11 = 18 inches (original length)
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Cheers,
Stan H.
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