Question 703344: CAN YOU HELP ME WITH THE FOLOWING PROBLEM?
3^2*4-6+(10-4)^3/2
Found 2 solutions by solver91311, AnlytcPhil:
Answer by solver91311(24713)   (Show Source):
Answer by AnlytcPhil(1806)  (Show Source):
You can put this solution on YOUR website!
He's a butt!
The priorities are
1. Do parentheses first, going left to right
2. Do exponents second, going left to right
3. Do multiplication or divisions third,
whichever come first going left to right
4. Do additions or subtractions third,
whichever come first going left to right
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3^2*4-6+(10-4)^3/2
We do the parentheses first, so instead of (10-4) we replace it with 6
3^2*4-6+6^3/2
-------------------------------------
Now there are no parentheses, so we get the first exponent going left
to right, so we replace 3^2 by 9
9*4-6+6^3/2
-------------------------------------
Now there are no parentheses, and now the first exponent going left
to right is 6^3, so we replace 6^3 by 216
9*4-6+216/2
-------------------------------------
Now there are no parentheses or exponents, so we get the first
multiplication or division going left to right, so we replace
9*4 by 36
36-6+216/2
-------------------------------------
There are no parentheses or exponents, so we get the first
multiplication or division going left to right, so we replace
216/2 by 108:
36-6+108
-------------------------------------
There are no parentheses, exponents, multiplication or division,
so we get the first addition or subtraction going left to right,
so we replace 36-6 by 30
30+108
-------------------------------------
Now there is only one thing left to do, to add those and get
138.
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Later on, you can learn to skip steps, but until you get used to
the procedure, just do one thing at a time and copy everything else
over. If you do things in the wrong order you will get wrong answers.
Edwin
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